C = {
    "-": "负",
    ".": "点",
    0: "零",
    1: "一",
    2: "二",
    3: "三",
    4: "四",
    5: "五",
    6: "六",
    7: "七",
    8: "八",
    9: "九",
    10: "十",
    100: "百",
    1000: "千",
    10000: "万",
    11: "十一",
    12: "十二",
    13: "十三",
    14: "十四",
    15: "十五",
    16: "十六",
    17: "十七",
    18: "十八",
    19: "十九",
}

D = {2: 10, 3: 100, 4: 1000, 5: 10000}


def to_chinese_numeral(n):
    # Check if n in C dictonary
    try:
        return C[n]
    except KeyError:
        pass

    # Check if negative
    if n < 0:
        n = abs(n)
        is_negative = True
    else:
        is_negative = False

    # Put single digits in list
    split_number = [int(x) for x in str(n)]

    arranged_number = []
    for _ in range(0, len(split_number)):
        arranged_number.append(split_number[0])
        if len(split_number) in D:
            arranged_number.append(D[len(split_number)])
        split_number.pop(0)
    if arranged_number[-1] == 0:
        arranged_number.pop(-1)

    if is_negative:
        arranged_number.append("-")

    return arranged_number


print(to_chinese_numeral(-90909))  # 9 10000 9